To find if the given number is an armstrong number or not.

#include <iostream.h>
# include <conio.h>
# include <math.h>
void main ()
{ clrscr();
int a,b=0,sum=0;
long int n;
cout<<"ENter the NO. : ";
cin>>n;
for(;n>0;)
//counts the digits
{ a=n%10;
n=n/10;
b++;
}
for(;n>0;)
{ a=n%10;
sum=sum+pow(a,b);
n=n/10;
}
if(sum==n)
{ cout<<"IT IS AN ARMSTRONG NUMBER...";
getch();
}
else
{ cout<<"IT IS NOT AN ARMSTRONG NUMBER...";
getch();
}
}